Question

.............. is calculated using the formula: x+y/4=11; 5x/6-y/3=17

Answer 1

Answer:

MEDIAN

Step-by-step explanation:

Answer 2

The value of  $x=\dfrac{190}{13},y=\dfrac{-47}{13}$

Step-by-step explanation:

Given : Equations $x+\frac{y}{4}=11,\ \frac{5x}{6}-\dfrac{y}{3}=17$

To find : Solve for x and y ?

Solution :

Let  $x+\dfrac{y}{4}=11$  .....(1)

$\dfrac{5x}{6}-\dfrac{y}{3}=17$  .....(2)

Multiply 8 on both sides of equation 1 and 6 on the both sides of equation 2, we get

$8(x+\dfrac{y}{4})=88\\\ 8x+2y=88$  .....(3)

$6(\dfrac{5x}{6}-\dfrac{y}{3})=6\times17\\\ 5x-2y=102$  .....(4)

Add (3) and (4), we get

$13x=190\\\\ x=\dfrac{190}{13}$

Put value of x in (1), we get

$\dfrac{190}{13}+\dfrac{y}{4}=11\\\\\Rightarrow\ \dfrac{y}{4}=11-\dfrac{190}{13}\\\\\Rightarrow\ \dfrac{y}{4}=\dfrac{-47}{13}$

Therefore, the value of  $x=\dfrac{190}{13},y=\dfrac{-47}{13}$

#Learn more  

Solve the following system of linear equations 103x+51y=617, 97x+49y=583

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