is can be possible to prove 1+1=3 plss help me
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41 – 40 = 61 – 60
=>16 + 25 – 2*5*4 = 36 + 25 – 2*5*6
=>4^2 + 5^2 -2*5*4 = 6^2 + 5^2 – 2*5*6
Using the identity: a^2 + b^2 - 2ab = (a - b)^2
=>(4 - 5)^2 = (6 - 5)^2
Taking square root both the sides:
=>(4 - 5) = (6 - 5) **
=>4 = 6
Dividing by 2
=>2 = 3
=>1 + 1 = 3
it's just hypothetical kinda a problem. there is no scientific ans
Hence proved!
subratsupkar:
Thanks bhai
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