is Compact circle or not
Answers
Answered by
10
COMPACT
then f is continuous, and the unit circle is f([0,2π]) and so it's a compact set of R2 as image of the compact [0,2π] by the continuous function f.
Answered by
4
then f is continuous, and the unit circle is f([0,2π]) and so it's a compact set of R2 as image of the compact [0,2π] by the continuous function f.
Similar questions