Question

is cos^2A/sin^2A = cot^2A
Plase explain

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Answer 1

Answer:

Cos ^ 2 a = b^2/h^2

Sin ^ 2 a = p ^ 2/h^2

Therefore b^2/ h^2/ p^2/ h^2=b^2/p^2=cot^2a

Hence Proven

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Step-by-step explanation:

Answer 2

Answer:

cos²A=b²/h² and sin²A=p²/h²

cos²A/sin²A=b²/h²/p²/h²

b²/p²=cot²A