Question

Is d is the HCF of 56 and 72 .find x and y satisfying d = 56 + x+ 72 y . Also show that x and y are not unique.​

Answer 1

Step-by-step explanation:

HCF of 56 and 72 = 2 = d

now d= 56+x+72y

2 = 56+x +72y

x + 72 y = 2-56 = -54

x + 72y = -54

if x = 0

0+72 y= -54

y = -54/72 = -3/4

if y= 0

x = -54

other values of x and y can be put in the similar manner so x and y are not unique.

Answer 2

you may go with the attached solution

how are you sis