Question

is divided by (x + 1).
(b) If (x - 3) is a factor of the polynomial (2x + x + k), find k.​

Answer 1

Answer:

$\\ x - 3 \\ x = + 3 \\ \\ p(x) = 2x + x + k \\ p(3) = 2(3) + 3 + k \\ \: \: \: \: \: \: \: \: \: \: = 6 + 3 + k \\ \: \: \: \: \: \: \: \: \: \: = 9 + k \\ \: \: \: - 9 = k$

Here's ur answer

Answer 2

Answer:

Step-by-step explanation:

We know if (x-3) is the factor then if we substitute 3 then the whole equation will equal to zero

2x+x+k

=2(3)+3+k=0 (substitute 3 for x)

=6+3+k=0

=9+k=0. Send 9 across the equal sign

=k=0-9

K=-9