Question

Is dropped from a height of 49 metre find the time interval in which the ball hits the ground the equal to 9.8 metre per second square.​

Answer 1

Answer:

t = √10 s

Explanation:

H = ut + 1/2 gt^2

49 = 0 + 1/2 (9.8) t^2

49 = 4.9t^2

t^2 = 49/4.9 = 10

t = √10 s