Math, asked by poonamvib, 7 months ago

is
Eight players - A, B, C, D, E, F, G and H - are standing
at their positions to play foot ball in a stadium. Dis 15 m
to the south of H and 10 m to the east of F, which is 15
m to the west of A. C is 5 m to the south of F and 5 m to
the west of B. G, D and. H forms a vertical straight line. D
stands exactly between G and H. E is to the north of B
and west of H.
to
aw
his
is
29. B is in which direction with respect to A?
(1) North (2) South (3) South-east
(4) South-west (5) North-east
30. E is at what distance with respect to H?
(1) 10 m (2) 15 m (3) ' 5 m
(4) 13 m (5) Cannot be determined
rk.
ich
31. G is approximately at what distance and in which
direction with respect to B?
(1) 11 m, South-east (2) 15 m, South-west
(3) 11 m, North-West (4) 12 m, North
(5) 15 m, North-east​

Answers

Answered by annieyan29
0

Answer:

                                                                   

Step-by-step explanation:

Answered by annasl
0

Answer:

(a) direction of B with respect to A : answer (4) south- west

(b) distance of E with respect to H

answer (3) 5 m

(c) G is in south- east direction with respect to B

distance between B and G  = 11 m

answer (1) 11 m, south- east

Step-by-step explanation:

given, there are 8 players: A, B, C, D, E, F, G, H

the respective positions of the players are shown in the image

refer to the attached image

(a) direction of B with respect to A : answer (4) south- west

B is in south west direction with respect to A

(b) distance of E with respect to H

distance between B and E is not given

in question, its only mentioned as E is to the north of B

but its mentioned as E is to the west of H

so we can assume that  E and H are in the same horizondal line

distance between E and E' = 5m = distance EH

answer (3) 5 m

(c) G is in south- east direction with respect to B

distance GD = 15 m, and DB'= 5m

then, GB' = 15-5 = 10 m

also, distance BB'= 5 m

then, BB'G forms a right triangle

apply pythagoras theorem

BG² = BB'² + B'G²

BG² = 5²+ 10²

BG² = 125

BG= √125 = 11.1

distance between B and G  = 11 m

answer (1) 11 m, south- east

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