Question

is equal to 2 and b is equal to 3 then find the value of following
(a) (1/a +1/b)^2​

Answer 1

$\huge\bf{\underline{\underline{\pink{Answer}}}}$

$\dfrac{25}{36}$

Answer 2

$\huge\sf\pink{Answer}$

☞ $\sf\bigg\lgroup \dfrac{1}{a} + \dfrac{1}{b}\bigg\rgroup^2 = \dfrac{25}{36}$

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$\huge\sf\blue{Given}$

✭ a = 2

✭ b = 3

$\rule{110}1$

$\huge\sf\gray{To \:Find}$

◈ $\sf \bigg\lgroup \dfrac{1}{a} + \dfrac{1}{b}\bigg\rgroup {}^{2}$

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$\huge\sf\purple{Steps}$

$\sf\underline{\underline{\green{Correct \ Question}}}$

If a = 2 and b = 3 , then find the value of (1/a+1/b)².

$\bullet\:\underline{\textsf{As Per the Question}}$

$\dashrightarrow\sf{\bigg\lgroup\dfrac{1}{a}+\dfrac{1}{b}\bigg\rgroup^2}$

Substituting the given values,

$\dashrightarrow\sf{\bigg\lgroup\dfrac{1}{2}+\dfrac{1}{3}\bigg\rgroup^2}$

$\dashrightarrow\sf{\bigg\lgroup\dfrac{3+2}{6}\bigg\rgroup^2}$

$\dashrightarrow\sf{\bigg\lgroup\dfrac{5}{6}\bigg\rgroup^2}$

$\orange{\dashrightarrow\sf{\dfrac{25}{36}}}$

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