Question

is equal to 7 minus 4 root 3 then what is the value of root a + 1 upon root a​

Answer 1

Answer:

Step-by-step explanation:

$WKT\\\\(x-y)^2=x^2+y^2-2xy\\\\Given\\\\a=7-4\sqrt{3}\\\\a=2^2+(\sqrt{3})^2-2(2)(\sqrt{3})\\\\a=(2-\sqrt{3})^2\\\\now\\\\\frac{a+1}{\sqrt{a}}\\\\=\sqrt{a}+\frac{1}{\sqrt{a}}\\\\=(2-\sqrt{3})+\frac{1}{(2-\sqrt{3})}\\\\=(2-\sqrt{3})+\frac{1}{(2-\sqrt{3})}\frac{(2+\sqrt{3})}{(2+\sqrt{3})}\\\\=(2-\sqrt{3})+(2+\sqrt{3})\\\\=4$

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Answer 2

Answer:

Step-by-step explanation:

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