is equation of hyperbola is 16x square - 8y sqaure+ 32 X - 48 Y =≤ 72 to the co-ordinate of focie
will be
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Answer:
Correct option is
D
Whose eccentricity is
3
19
Given equation is
16(x
2
−2x)−3(y
2
−4y)=44
⇒16(x−1)
2
−3(y−2)
2
=44+16−12
⇒16(x−1)
2
−3(y−2)
2
=48
⇒
3
(x−1)
2
−
16
(y−2)
2
=1
Here, centre (1,−2), length of transverse axis
=2a=2×
3
=2
3
Length of conjugate axis =2b=2×4=8
and eccentricity, e=
1+
a
2
b
2
=
1+(
3
4
)
2
=
1+
3
16
=
3
19
.
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