Math, asked by mohammadtulaib586, 23 hours ago

is equation of hyperbola is 16x square - 8y sqaure+ 32 X - 48 Y =≤ 72 to the co-ordinate of focie
will be​

Answers

Answered by kumarisunitayadav05
0

Answer:

Correct option is

D

Whose eccentricity is

3

19

Given equation is

16(x

2

−2x)−3(y

2

−4y)=44

⇒16(x−1)

2

−3(y−2)

2

=44+16−12

⇒16(x−1)

2

−3(y−2)

2

=48

3

(x−1)

2

16

(y−2)

2

=1

Here, centre (1,−2), length of transverse axis

=2a=2×

3

=2

3

Length of conjugate axis =2b=2×4=8

and eccentricity, e=

1+

a

2

b

2

=

1+(

3

4

)

2

=

1+

3

16

=

3

19

.

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