Math, asked by Ishaan20, 1 year ago

Is f(x) =(1+x)^1/x,when x is not equal to 0 and f(x)=e, when x=0 continuous at x=0.

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Answered by kvnmurty
6
By definition:    Euler's exponential function is defined as:
          eⁿ =  Lim x -> 0,  (1 + x n)^(1/x)    or,
                                      (1 + n / x )^x

Given    f(x) = (1 + x)^(1/x)   when x ≠ 0
 So  Lim x -> 0 ,  f(x) = Lim x -> 0,  (1 + 1* x)^(1/x)
                                  = e¹ = e.
Also given  f(0) = e.

Since the limit as x tends to 0 is same as f(0) , the function f(x) is continuous at x = 0.
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kvnmurty: :-)
kvnmurty: Alternately we can use the L'Hopital rule. Find Ln (f(x)).
Then, Differentiate the numerator and denominator and apply limits afterwards. We get it.
Ishaan20: thnx great help
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