Math, asked by prafullakumardash14, 1 day ago

is form of 16000 is invested from 3 years at 10% per annum interest compounded annually
a what is the sum due at end of 1st year
b what is the sum due at end of second year
c what is the compound interest in 2 years
d what is the interest earned in second year
e what is the sum due at the end of 3 years ​

Answers

Answered by jayesh2773
1

the ⇒ P=Rs.16000,R=10%

⇒ C.I. for second year = P×

100

R

×(1+

100

R

)

⇒ = 16000×

100

10

×(1+

100

10

)

⇒ = 1600×

10

11

⇒ C.I. for second year = Rs.1760. of second year will be

Answered by lodhiyal16
2

Answer:

Step-by-step explanation:

Principal = 16000

Time = 3 years

Rate = 10%

A. For 1 st year

S.I = P × R × T/100

= 16000 × 10 × 3 /100

= 4800

Amount = P + I = 16000 + 4800

B. For 2nd year

S.I = P × R × T/100

= 20800 × 10 × 3 /100

= 6240

Amount = P + I = 20800 + 6240

= 28040

C.   ⇒  P=Rs.16000,R=10%

⇒  C.I. for second year = P× R/ 100 ×(1+ R/100 )

⇒  = 16000× 10/100 ×(1+ 10/100)

⇒  = 1600× 11/10

⇒  C.I. for second year = Rs.1760.

D. S.I = P × R × T/100

= 20800 × 10 × 3 /100

= 6240

E. S.I = P × R × T/100

= 28040× 10 × 3 /100

= 8412

Amount = P + I = 28040 + 8412

= Rs. 36452

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