Question

is found to be 40 m longer when the Sun’s altitude is 30° than when it is 60°. Find the height of the jsuisjzuududnfhsj​

Answer 1

Answer:

the new distance will be same

= 40 m .

refer to the attachment, you will get the answer.

Step-by-step explanation:

hope it helps ✔✔

Answer 2

Answer:

Let us assume, AB = h m, BC = x m

DB = (40 +x) m

In right triangle ABC,

tan 60° = AB/BC

√3 = h/x

h = √3 x……….(i)

In right triangle ABD,

tan 30° = AB/BD

1/√3 =h/(x + 40) ……..(ii)

From (i) and (ii),

x(√3 )(√3 ) = x + 40

3x = x + 40

2x = 40

x = 20

Substituting x = 20 in (i),

h = 20√3

Hence, the height of the tower is 20√3 m.