Question

is found to be 40 m longer when the Sun’s altitude is 30° than when it is 60°. Find the height of ​

Answer 1

Explanation:

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Answer 2

Answer:

Let us assume, AB = h m, BC = x m

DB = (40 +x) m

In right triangle ABC,

tan 60° = AB/BC

√3 = h/x

h = √3 x……….(i)

In right triangle ABD,

tan 30° = AB/BD

1/√3 =h/(x + 40) ……..(ii)

From (i) and (ii),

x(√3 )(√3 ) = x + 403x = x + 402x = 40x = 20

Substituting x = 20 in (i),

h = 20√3

Hence, the height of the tower is 20√3 m.

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