is given that ΔABC ≅ΔFDE and AB = 5 cm, ∠B = 40° and ∠A = 80°. Then which of the following is
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∆ABC congruence to ∆FDE ,
then,
AB = FD
BC=DE
AC=FE
and
angle ABC = angle FDE
angle BCA = angle DEF
angle CAB =angle EFD
now, given, angle ABC = 40° and angle CAB = 80° and AB = 5 cm
so, angle FDE = 40° and angle EFD= 80°
and FD = 5 cm
also DF = 5 cm
and angle DEF = 60°
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