Is integration by parts necessary to solve ∫x4ex5?
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No not necessary. It can be solved by method of substitution
Let x⁵ = a
da/dx = 5x⁴ ===> da/5 = x⁴dx
Now ,
∫eᵃ.da/5 = eᵃ/5
Substituting back a we get
eˣ⁵/5
jay1001:
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