Is is possible to prove a cylic trapizium into isosceles trapizium ?
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Use the property of cyclic trapezium as well as parallelogram to prove the answer. ... Hence, cyclic trapezium ABCD is isosceles as the opposite sides which are not parallel are equal.
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3
Answer:
Let ABCD be a cyclic trapezium, with AB || DC and AB is shorter than CD.
There are 4 angles in a trapezium and the trapezium is cyclic the opposite angles must be supplementary. Thus <A + <C = 180 deg. and <B + <D = 180 deg.
If AB and CD are parallel to each other, <A + <D = 180 deg. and <B + <C = 180 deg.
So <A + <C = 180 = <A + <D or <C = <D and acute.
Similarly, <B + <D = 180 = <A + <D or <A = <B and obtuse.
Thus the adjacent angle on parallel sides are equal. Therefore the trapezium is isosceles as well as cyclic,
hence, proved
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