is it correct.........?plz answer
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Answered by
3
★Heya★
No
Right way of solving this is
2x² - 25 = 0
=>
(√2x)² - ( 5 )² = 0
=>
( √2x - 5 ) × ( √2x + 5 ) = 0
=>
( √2x - 5 ) = 0 OR ( √2x + 5 ) = 0
=>
x = 5/√2 OR x = -5/√2
=>
x = 5√2/2 OR x = -5√2/2
No
Right way of solving this is
2x² - 25 = 0
=>
(√2x)² - ( 5 )² = 0
=>
( √2x - 5 ) × ( √2x + 5 ) = 0
=>
( √2x - 5 ) = 0 OR ( √2x + 5 ) = 0
=>
x = 5/√2 OR x = -5/√2
=>
x = 5√2/2 OR x = -5√2/2
Answered by
4
Answer:
No dear...
There are some things in which you lacked behind...
Step-by-step explanation:
Becoz
if you are using the formulae a^2-b^2=(a+b)(a-b)
Then in second line, you have to have write (√2x)^2-(5)^2
You have written 2x^2-(5)^2
And then in third line it will be
(√2x+5)(√2x-5)
And so on...
Hope It Helps
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