Question

Is it possible for a charged block of total Q charge to leave the contract with the ground if is it slide from a inclined plane. If possible find its velocity when it leaves the ground .

Answer 1

Answer:

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Total force exerted by block =mg, thus inclined plane also exerts the same force back. This can be seen as follows:

Normal Force due to inclined plane on block =mgcosθ

Friction force =mgsinθ

Thus total force =mg

$cos </p><p>2</p><p> θ+sin </p><p>2</p><p> θ$

(because normal and friction forces are perpendicular to each other.

Answer 2

Answer:

Refer the attachment

Explanation:

Hope it helps you