Is it possible that the sum of any consecutive ten terms of the sequence is 500?Why?
First term is 2
Common difference is 4
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0
Answer:
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Answered by
4
Answer:
I think no
Step-by-step explanation:
Sn = n/2 [2f+(n-1)d]
S10= 10/2[4+9*4]
=5*40
=200
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