Math, asked by nehaak873, 4 months ago

Is it possible to construct a quadrilateral HARD with HA=3cm, AR=4cm,RD=5.4cm,HD=5.9cm and HR=8cm?If not, give reason;if yes, construct the quadrilateral.​

Answers

Answered by priyel
2

Step-by-step explanation:

\bf \: Given  \: measures \: are :  -   \\  \bf\:HA=3cm,AR=4cm,\\\bf\:RD=5.4cm,HD=59cm  \: and  \: HR=8cm \\  \\  \bf Here,  \: consider \:  the \: triangle  \: ABC\\\\\bf  \: within \:  the  \: quadrilateral. \\  \\ \bf \:AB+BC=3+4=7cm \: and \: AC =8cm  \\  \\ \bf \:i.e., the \:  sum  \: of  \: two  \: sides \:  of \:  a  \: triangle \\\\\bf\:  is  \: less \:  than \:  the  \: third  \: side, \:  which \:  is  \: absurd.  \\  \\ \bf \:Hence,  \: we  \: cannot  \: construct  \: such  \: a \:  quadrilateral. 

Answered by bantisaw01
1

Answer:

yes it is possible.........

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