Question

Is it possible to construct a rhombus ABCD where AC = 6cm and BD = 7 cm ? Justify your answer .
Explain with diagram
If it helps I will mark you as brainleist​

Answer 1

Step-by-step explanation:

1. Draw a diagonal AC=6 cm.

2. Draw a perpendicular bisector of AC, let the perpendicular bisector and AC intersects at O (∵ Diagonals of rhombus intersects at right angle)

3. Taking O as centre and half of the length of another diagonal (i.e 3.5 cm) as radius, mark arc on the perpendicular bisector at both sides of AC. Name these intersection points as B and D

4. Join AB,AD,BC,CD.

5. ABCD is the required rhombus

6. Measure the ∠ABD which come out to be 40.7˚

Answer 2

Answer:

yes

Step-by-step explanation:

Draw a diagonal AC=6 cm.

2. Draw a perpendicular bisector of AC, let the perpendicular bisector and AC intersects at O (∵ Diagonals of rhombus intersects at right angle)

3. Taking O as centre and half of the length of another diagonal (i.e 3.5 cm) as radius, mark arc on the perpendicular bisector at both sides of AC. Name these intersection points as B and D

4. Join AB,AD,BC,CD.

5. ABCD is the required rhombus.

6. Measure the ∠ABD which come out to be 40.7˚

solution

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