Math, asked by dinesh2503, 1 year ago

is it possible to construct rhombus PQRS with pr=7cm and qs=5cm ?if yes, construct it. if not state reason​for it

Answers

Answered by chbilalakbar
6

Answer:

Solution:

Yes it is possible to construct the rhombus PQRS

where

          PR = 7 cm

          QS = 5 cm

Procedure to draw:

1)  Draw the line PR of length 7 cm.

2) Draw the perpendicular Bisector of line PR.

3) Considering the origin the point of intersect of lines, draw the Arcs of length 2.5 cm and name the points Q and S where the Arcs insect the bisector of line PR

4) Joint the point P with Q and S.

5) Joint the point R with Q and S.

The rhombus is ready which have four equal sides and each side have  length  √(18.2)

Answered by amitnrw
2

Answer:

Yes it is possible to Construct rhombus PQRS with PR = 7 cm & QS = 5 cm

All sides equal to 4.3 cm

Step-by-step explanation:

Yes it is possible to Construct rhombus PQRS with

PR = 7 cm

QS = 5 cm

PR & QS are diagonals

so side of rhombus

= √(( PR/2)² + (QS/2)² )

= √( (7/2)² + (5/2)²)

= √ (49/4 + 25/4)

= √74/4

= √18.5

= 4.3 cm

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