Is it possible to design a rectangular mango grove whose length is twice its breadth, and the area is 800 m²? If so, find its length and breadth.
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Let the breadth be ‘a’ m
Given, rectangular mango grove whose length is twice its breadth.
Length = 2 × Breadth = 2a
Area of rectangular mango = 800 m²
⇒ 2a × a = 800
⇒ a² = 400
⇒ a = 20 m
Thus, length = 40m , Breadth = 20m
therefore , it is clear that it is possible to design a rectangular mango grove whose length is twice its breadth, and the area is 800 m² and also length = 40m and Breadth = 20m
Given, rectangular mango grove whose length is twice its breadth.
Length = 2 × Breadth = 2a
Area of rectangular mango = 800 m²
⇒ 2a × a = 800
⇒ a² = 400
⇒ a = 20 m
Thus, length = 40m , Breadth = 20m
therefore , it is clear that it is possible to design a rectangular mango grove whose length is twice its breadth, and the area is 800 m² and also length = 40m and Breadth = 20m
Answered by
25
SOLUTION :
Given :
Area of a rectangular mango grove = 800 m²
Let breadth of a rectangular Mangrove = x m
length of a rectangular Mangrove = 2x
[Given : length is twice its breadth]
A.T.Q,
Area of a rectangular mango grove = Length × breadth
800 m² = 2x × x
2x² = 800
x² = 800/2 = 400
x = √400
x = ±20
[Breadth can never be negative]
So, x = 20
Breadth of a rectangular Mangrove = x = 20 m
Breadth of a rectangular Mangrove = 20 m
Length of a rectangular Mangrove =2x = 2×20 = 40 m
Hence , the Length of a rectangular Mangrove= 40 m & Breadth of a rectangular Mangrove = 20 m.
∴ It is possible to design a rectangular mango grove having area 800 m² and length = 40 m & breadth = 20 m.
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