Is it possible to design a rectangular park of perimeter 80 m and area 400 m square ? if so, find its length and breadth.
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Hola‼.........❤✌
Let length of the rectangular park be x m and breadth be y m.
According to question,
perimeter = 80 m ⇒ 2(l + b) = 80 m
⇒ 2 (x + y) = 80
⇒ x + y = 40
=> y = 40-x
i.e, breadth =(40- x) m
Now, area = 400
=> l×b = 40
=> x (40-x) = 400
=> x^2 -40x +400 = 0
Here, a = 1, b = –40, c = 400
Now, D = b^2 – 4ac
= (-40)^2 – 4(1) (400) = 1600 – 1600 = 0
Since, D=0
So, the given quadratic equation has equal roots and hence it is possible to design a rectangular park.
Now, solving the the quadratic equation x^2 - 40x +400 by quadratic formula, we get
x= -b +- √D/ 2a
= 40/2
= 20
Hence, length of the rectangular park, x = 20 m
& breath = (40-x) = 20 m
Hope it's helpful.... ☺
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