Is it possible to design a rectangular park of perimeter 80 m and area 800m².if so, find length and breadth.
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The breadth of the rectangular park=( x)m
perimeter = 80m
therefore,
perimeter of a rectangle = 2( l+b)
2(l+b) = 80
=2(x+400/x)=80
= X2+400/x = 80/2
= X2 + 400/x = 40
= X2 + 400 = 40x
= x2 - 40x + 400 = 0
here,
a=1 , b = -40 , c = 400
b2 - 4ac
= (-40)2 - 4.1.(400)
= 1600-1600
= 0
therefore it is possible
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