Is it possible to design a rectangular park of perimeter 80m and area 400m² ? If so, find its length and breadth.
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Answer:
Let Length be x ,
Given that,
Perimeter = 80m
2 (L+B) = 80m
(L+B) = 80/2
(x+B) = 40m
Breadth = 40 - x
Also given that Area = 400m²
Length × Breadth = 400m²
x (40-x) = 400
40x - x² = 400
40x - x² - 400 = 0
0 = -40x + x² + 400 = 0
-40x + x² + 400 = 0
x² - 40x + 400 = 0
We factorize by
By splitting the middle term,
x² - 20x - 20x + 400 = 0
x (x-20) - 20 (x-20) = 0
(x-20) (x-20) = 0
So the root of the equation are,
x - 20 = 0 x - 20 = 0
x = 20 x = 20
So, x = 20 is the solution.
•Length = x = 20m
• Breadth = 40-x = 40-20 = 20m
Hope it Helps....✌✌
~Tavishi♥
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Answer:
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