Math, asked by monikatiwari1155, 4 months ago

Is it possible to design a rectangular park of perimeter 80m and area 400m² ? If so, find its length and breadth. ​

Answers

Answered by Anonymous
3

Answer:

Let Length be x ,

Given that,

Perimeter = 80m

2 (L+B) = 80m

(L+B) = 80/2

(x+B) = 40m

Breadth = 40 - x

Also given that Area = 400m²

Length × Breadth = 400m²

x (40-x) = 400

40x - x² = 400

40x - x² - 400 = 0

0 = -40x + x² + 400 = 0

-40x + x² + 400 = 0

x² - 40x + 400 = 0

We factorize by

By splitting the middle term,

x² - 20x - 20x + 400 = 0

x (x-20) - 20 (x-20) = 0

(x-20) (x-20) = 0

So the root of the equation are,

x - 20 = 0 x - 20 = 0

x = 20 x = 20

So, x = 20 is the solution.

•Length = x = 20m

• Breadth = 40-x = 40-20 = 20m

Hope it Helps....

~Tavishi

Answered by jay419
2

Answer:

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