is it possible to design a rectangular Park of perimeter 80m and area 400 m square if so find its length and breadth
Answers
Answered by
6
perimeter of a rectangle =2(l+b)
80=2(l+b)
40=l+b
l=40-b
AREA OF A RECTANGLE= l*b
400=(40-b)*b
400=40b-b² (middle term spiliting)
b²-40b+400=0
b²-20b-20b+400=0
b(b-20)-20(b-20)=0
(b-20)(b-20)=0
b-20=0
b=20m
l=40-b
l=20m
80=2(l+b)
40=l+b
l=40-b
AREA OF A RECTANGLE= l*b
400=(40-b)*b
400=40b-b² (middle term spiliting)
b²-40b+400=0
b²-20b-20b+400=0
b(b-20)-20(b-20)=0
(b-20)(b-20)=0
b-20=0
b=20m
l=40-b
l=20m
murli126:
thx
Answered by
0
yes it is possible
l×b=400. (1)
|+B=80
l=80-b
put in (1)
(80-b)×b=400
80b-b^2=400
b^2-80b+400
then find the factors to solve it
l×b=400. (1)
|+B=80
l=80-b
put in (1)
(80-b)×b=400
80b-b^2=400
b^2-80b+400
then find the factors to solve it
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