Question

is it possible to design a rectangular Park of perimeter 80m and area 400 m square if so find the length and breadth

Answer 1

Here your answer goes

Step :- 1

Let the length be x m

Then Breadth be y m

Therefore , Perimeter = 80 m

Step :- 2

According to question

2 ( x + y ) = 80

x +  y = 40 ------->> 1

Also , Area = 400 m^2

x * y = 400

x = ( 40 - x ) =400

Step :- 3

Using equation 1

40x - x - x^2 = 400

==>> x^2 - 40x + 400 = 0 -----> 2

Step :- 4

The equation 2 is a quadratic equation where ,

a = 1

b = -40

C = 400

Therefore , its length and breadth given by

x^2 - 40x + 400

( x- 20 )^2 =0

x = 20 , 20

Therefore , the length of rectangular field be 20 m and Breadth be 20 m

↓↓

Be Brainly

Together we go far

Answer 2

let the length of park be x m
and the breadth be y m
ACC to 1st condition,
perimeter = 80m
2(x+y) = 80
x + y = 40 ......(1)
ACC to 2nd condition,
area = 400m
xy = 400. .......(2)
from (1),
x = 40 - y. (3)
put the value of x in (2),
(40-y)y = 400
40y - y² = 400
y² - 40y + 400 = 0
y² - 20y - 20y + 400 = 0
y(y - 20) - 20(y - 20) = 0
y -20 = 0
y = 20
put y = 20 in (3),
x = 40-20
x = 20
there it is possible to create a rectangular park with given dimensions