Is it possible to design a rectangular park whose perimeter is 6 times its breadth and area is 800 metre square.If possible find its length and breadth .
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Let the length of rectangular park be l m.
Let the breadth of rectangular park be b m.
Given,
Perimeter = 6*b m
Area = 800 m^2
We know,
Perimeter of a rectangle = 2*(l+b)
Area of a rectangle = l*b
We have,
Perimeter of the rectangular park = 6*b
2*(l+b) = 6*b
2l + 2b = 6b
2l = 4b
l = 2b.....(1)
And again,
Area of rectangular Park = 800 m^2
l*b = 800
2b*b = 800....{from (1)},
2*b^2 = 800
b^2 = 400
b = 20 m.... (2)
Now from (1) and (2),
l = 40m
So, length and breath of the rectangular park are 20 m and 40 m respectively.
Let the breadth of rectangular park be b m.
Given,
Perimeter = 6*b m
Area = 800 m^2
We know,
Perimeter of a rectangle = 2*(l+b)
Area of a rectangle = l*b
We have,
Perimeter of the rectangular park = 6*b
2*(l+b) = 6*b
2l + 2b = 6b
2l = 4b
l = 2b.....(1)
And again,
Area of rectangular Park = 800 m^2
l*b = 800
2b*b = 800....{from (1)},
2*b^2 = 800
b^2 = 400
b = 20 m.... (2)
Now from (1) and (2),
l = 40m
So, length and breath of the rectangular park are 20 m and 40 m respectively.
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