Is it possible to draw a triangle with sides AB = 25cm , BC = 14 cm and AC = 19 cm ? Give reason
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Answer:
Here altitude from A to BC is AD, we know in isosceles altitude on non equal sides also median,
so, BD=CD=2BC=214=7cm
Now, we applying Pythagoras theorem in △ABD,
AB2=BD2+AD2
(25)2=(7)2+AD2
AD2=625−49
AD2=576
AD=24cm
∴ Altitude from A to BC=AD=24cm
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