Question

is it possible to drawn a rectangle whoes breadth is 1/4 of its length and area 16msq if so find its perimeter

Answer 1

☆Hey Mate☆

Its possible!

If we assume legth as x
then,breadth= x/4

$16 {m}^{2} = x \times \: \frac{ x }{4} \\ 16 {m}^{2} = \frac{ {x}^{2} }{4} \\ 16 {m}^{2} \times 4 = {x}^{2} \\ \sqrt{64 {m}^{2} } = x \\ 8m = x$

Then, breadth = 8/4 = 2m

Perimter of rectangle = 2( length + breadth )
= 2 ( 8m + 2 m )
= 2 × 10 m
= 20 m

Hope it helps☺!