is it possible to find the value of log 100 to the base 1 ? explain
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One way we can approach log problems is to remember that
ab=c
⇔log ac=b
In our question, since the value of
a
in the right hand side log isn't specifically listed, it's assumed to be 10. So what we have is:
ab=c⇔log10(100)=b
10b=100⇔log10(100)=b
By observation of the left hand side, we can see that b=2
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