is it possible to have a polygon the sum of whose interior angle is 1120
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Answered by
3
Answer:
If n= number of sides
- (n-2) ×180=sum of interior angles
- So (n-2)×180=1120
- (n-2) = 1120/180
- n-2 = 6.22222222
- n = 6.22222222 + 2
- n = 8.22222222
The number of sides come in the form of decimal.
So it can't be possible
Answered by
0
Answer:
Нет, и никогда у вас не будет таких вопросов, никогда не мадарчод
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