is it possible to have a regular polygon whose interior angle is 52°?
give reasons.
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Answer:
No
Step-by-step explanation:
for any polygon ( a closed region with more than 3 sides), summation of every exterior angle must be equal to 360°
here exterior angle will be, 180 - 52 = 128
and 360 is not divisible by 128
it means, if we divide 360 by 128 it gives around 2.8125 which is not an integer. ( number of sides of the polygon should be integer.)
so any polygon with interior angle 52° is not possible.
I hope this will help you.
Thank you.
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