Math, asked by shankersharma1979, 1 year ago

Is it solve or not ???? Plz answer it

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Answers

Answered by RitikaWasil
1

Answer:

we can only take a square common from this.

and we will get

 { a}^{2} (2 - a)

Answered by AbhijithPrakash
0

Answer:

\mathrm{Factor}\:2a^2-a^3:\quad -a^2\left(a-2\right)

Step-by-step explanation:

2a^2-a^3

\mathrm{Apply\:exponent\:rule}:\quad \:a^{b+c}=a^ba^c

a^3=aa^2

=-aa^2+2a^2

\mathrm{Factor\:out\:common\:term\:}-a^2

=-a^2\left(a-2\right)

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