Question

is it true that for any sets A andB,
P(A) U P(B) = P(AUB)? Justify your
answer ​

Answer 1

Step-by-step explanation:

Let A={0,1} and B={1,2}

∴A∪B={0,1,2}

P(A)={ϕ,{0},{1},{0,1}}

P(B)={ϕ,{1},{2},{1,2}}

P(A∪B)={ϕ,{0},{1},{2},{0,1},{1,2},{0,2},{0,1,2}}

P(A)∪P(B)={ϕ,{0},{1},{0,1},{2},{1,2}}

∴P(A)∪P(B)



=P(A∪B)

False