Is kinetic energy of a body is increased by 300% what percentage will linear momentum of body increase
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2
Answer:
increases by 100%
Explanation:
p= (2mKE)^1/2
here p is momentum and KE is kinetic energy
initially
p=2mKE
now ke is increased by 300%
so KE × 300/100
=3KE
Hence new KE is
KE"= KE +3KE
= 4KE
Now
p"= (2mKE")^1/2
= (2m4KE)^1/2
=2(2mKE)^1/2
p" = 2p
So % change in momentum is
p"-p/p ×100
2p-p/p ×100
=100%
Hope I was able to solve your doubt
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