Question

is log 2 rational or irrational? justify your answer

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Answer 1

Answer:

Let us assume log 2 is as rational number,that is log 2

= p/q

Where p,q are integers,since log 1=0

and log 10= 1,0<log2<1 and p<q.

2= 10^p/q

2^p= (2×5)^q

2^q-p=5^p

where q - p is an integer greater than 0.

Now,it can be seen that the LHS is even and RHS is odd.

Hence there is contradiction and log 2 is irrational.

Step-by-step explanation:

Hope it helps you ❣️❣️

${ \huge \blue be brainly..}$