Question

is -(log cos x) equal to log (secx)?​

Answer 1

Step-by-step explanation:

log|sec x| = log|1/cos x| = log1 - log |cos x| = 0 - log |cos x| = -log |cos x|

(Since, log 1 = 0)

Answer 2

$\bf{a^b = c \iff b = \log_a(c).}$

ㄒhαnkuh :)