Question

is mid point of side AB of triangle ABC, therefore CP is a/an *​

Answer 1

Step-by-step explanation:

△PBC and △QBC,

BC=BC (Common)

As AB=BC

∠ABC=∠ACB (Isosceles triangle property)

PB=QC (AB = AC and P , Q are mid points of AB and AC respectively)

Thus, △PBC≅△QCB

Hence, CP=BQ (Corresponding sides)