Chemistry, asked by babylover, 1 year ago

Is N2 + 3H2 →2NH3 a balanced chemical equation? Is it obeying the law of conservation of matter? Question 6 options: No, the equation is not balanced. The Nitrogen (N) is balanced, but they Hydrogen (H) is not balanced. No, the equation is not balanced. The Nitrogen (N) and Hydrogen (H) atoms are not balanced. No, the equation is not balanced. The Hydrogen (H) is balanced, but they Nitrogen (N) is not balanced. Yes, the equation is balanced. There are the same number of Nitrogen (N) and Hydrogen (H) atoms on each side of the equation.

Answers

Answered by khanaffanullah
98

HEY!!

here is ur answer

 

  In general before one attempts to balance the masses in a chemical reaction is necessary to determine first if there is a change of oxidation state  (* ) from the reactants to the product of the reaction..If there is a change the total units of oxidation-reduction must be first balanced before balancing the mass.

In this case :   N2 + H2 = NH3   N2 is in the 0 oxidation state ( uncombined) and as a product in NH3

is in the -3 oxidation state ( because it is combined with 3H+) this means  there is a reduction of 3 units per N atom  and a total of 6 for the 2 atoms reacting.. now H is in the 0 oxidation state also and is oxidized to the +1 state in the product NH3 and since there are 2 of them the total oxidation units are2.

 A reaction requires the number of oxidation units to be equal to the reduction units. We can obtain this by using 3 molecules of H . If we use 3H2,the equation will be balanced in redox units.

 

 

             N2+ 3H2  = NH3

 

Now the mass balance.

There are 2 N on the left and only one on the right. a coefficient of 2 for NH3 will satisfy the mass requirements  ( 2N,left; 2N right; 6H left; 6H right )

 

                                   N2 + 3H2  = 2 NH3

 

Mark me as brainliest ^_^xP

Answered by yxmii
3

Answer:

yes. it can be balanced

N2 + H2 = NH3   N2 is in the 0 oxidation state ( uncombined) and as a product in NH3

Explanation:

Similar questions