Question

IS NOT QUESTION OK:-In
trapezium ABCD, side AB || side CD, diagonal AC and BD intersect each
other at point P. Then prove
that.A(∆ABC)/A(∆CPD)=AB^2/CD^2
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Answer 1

Explanation:

Since △APDand△BPC are on the same base and between the same parallels, then we can conclude that the ratio of their areas will be the ratio of their bases.

Since △APDand△BPC are on the same base and between the same parallels, then we can conclude that the ratio of their areas will be the ratio of their bases.Hence Area of △APD : Area of △BPC = AP:CP