Question

is one of the root of the equation X square + 6 X + k= 0 is a 4 The Other root is -10

Answer 1

Answer:

⇒  The given quadratic equation is 8x2−6x+k=0, comparing it with ax2+bx+c.

⇒  Then, a=8,b=−6,c=k

⇒  It is given that one root of this equation is square of the other root. So, if we assume one root to be p, the other root can be p2. So, we assume the roots to be pand p2.

⇒  Sum of the roots =a−b

∴  p+p2=8−(−6)

∴  p+p2=43

∴  4p+4p2=3

∴  4p2+4p−3=0              ----------- ( 1 )

⇒  Product of the roots =ac

∴  p×p2=8k

∴  p3=8k          ------- ( 2 )

⇒  4p2+4p−3=0        [ From ( 1 ) ]

⇒  4p2−2p+6p−