Question

Is one of the zeros of the polynomial x3 - 6x2 + 2x - 12.

Answer 1

Good Morning/ Afternoon/ night :)

One of the zeroes of

$= > x ^{3} - 6x ^{2} + 2x - 12$

is :

$first \: factorise \: it \\ \\ = > (x^{3} - 6x ^{2} ) + (2x - 12) \\ = > x ^{2} (x - 6) + 2(x - 6) \\ (x - 6)(x ^{2} + 2) \\ \\ \\ now \: equate \: its \: factors \: to \: 0$

$= > x - 6 = 0 \\ = > x = 6$

As You wanted only one zero of that polynomial so i found only 1

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