Question

is one zero of the polynomial p(x) ≈ x²-x+k is 3 find the value of k
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Answer 1

Answer:

$x {}^{2} - x + k = 0$

$x = 3$

$(3) {}^{2} - 3 + k = 0$

$9 - 3 + k = 0$

$k = - 6$

I hope this answer may help you

Answer 2

Step-by-step explanation:

$if \: 3 \: is \: the \: zero \: of \: the \: {x}^{2} - x + k \\ then \: p(3) = 0 \\ {3}^{2} - 3 + k = 0 \\ 9 - 3 + k = 0 \\ 6 + k = 0 \\ k = - 6$