Question

is p (3+4p) = 5 a quadratic equation? give reasin for your answer​

Answer 1

Answer:

n+5 = 19 (n=1)

1+5\ =\ 4\ \ne\ n+5\ =\ 19\1+5 = 4

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= n+5 = 19

(b) 7n+5 = 19 (n=-2)

7\times\left(-2\right)\ +\ 5\ =\ 19\7×(−2) + 5 = 19

-14+5\ =\ 19\−14+5 = 19

9\ne199

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=19

(c) 7n+5 = 19 (n=2)

7\times2+5=19\7×2+5=19

14+5\ =\ 19\14+5 = 19

19=1919=19

(d) 4p-3 = 13 (p=1)

4\times1-3=13\4×1−3=13

4-3=134−3=13

1\ne13\1

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=13

(e) 4p-3 = 13 (p=-4)

4\left(-4\right)\ -3\ =\ 134(−4) −3 = 13

-16\ -3\ =\ 13\−16 −3 = 13

-19\ \ne13−19

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=13

(f) 4p-3 = 13 (p=0)

4\times0\ -3=134×0 −3=13

0-3=130−3=13

-3\ne13−3

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=13