Is polynomial y4 + 4y2 + 5 have zeroes or not?
Answers
Answered by
76
★ QUADRATIC RESOLUTION ★
The Bi quadratic function can have roots for sure ,
Consider y² = t
The previous equation will reduce to
t² + 4t + 5 = 0
Now resolution into the quadratic equation above , will yield imaginary roots ,
In fact , the earlier equation will reduce into complex conjugate pairs , aslike it's quadratic has imaginary resolution , every polynomialic equation can have roots , maybe real or imaginary depending upon the coefficients and degree of given equation
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The Bi quadratic function can have roots for sure ,
Consider y² = t
The previous equation will reduce to
t² + 4t + 5 = 0
Now resolution into the quadratic equation above , will yield imaginary roots ,
In fact , the earlier equation will reduce into complex conjugate pairs , aslike it's quadratic has imaginary resolution , every polynomialic equation can have roots , maybe real or imaginary depending upon the coefficients and degree of given equation
★✩★✩★✩★✩★✩★✩★✩★✩★✩★✩★
Answered by
20
Answer:
Step-by-step explanation:
★ QUADRATIC RESOLUTION ★
The Bi quadratic function can have roots for sure ,
Consider y² = t
The previous equation will reduce to
t² + 4t + 5 = 0
Now resolution into the quadratic equation above , will yield imaginary roots ,
In fact , the earlier equation will reduce into complex conjugate pairs , aslike it's quadratic has imaginary resolution , every polynomialic equation can have roots , maybe real or imaginary depending upon the coefficients and degree of given equation
★✩★✩★✩★✩★✩★✩★✩★✩★✩★✩★
hope it helps you...............................................................
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