Question

is projected at angle 30° to the horizontal with a velocity of 39.2 metre per second find time of ascent​

Answer 1

Answer:

Answer

The time of flight is given by

T=

g

2usinθ

=

10

2×30×1/2

=3 s

Thus, after 1.5 s the body will be at the highest point.

So the direction of motion will be horizontal after 1.5 s, the angle with the horizontal is 0

∘

.